Bryna Kra gave a talk (last Thursday (January 24, 2013)) at Orsay about her joint work with Van Cyr on Nivat’s conjecture. The talk was peculiar in several aspects: despite the remarkable fact that Bryna was speaking in French while writing in English at the blackboard (at normal pace without mixing up the languages!), she was able to successfully explains some of the dynamical ideas behind her joint paper with V. Cyr. In particular, I thought that the readers of this blog who missed Bryna’s talk(s) on this subject could benefit from my notes that I’ll transcript below.
1. Introduction
Let be a finite alphabet and
a (bi-infinite) word,
.
We define as the number of configurations (words) in
of length
. Intuitively, the quantities
measure how complicated the word
at finite scales, and this is why
is called complexity function.
We say that is periodic if there exists
(called a period of
) such that
for all
.
Theorem 1 (Morse-Hedlund (1940)) A word
is periodic if and only if there exists
such that
.
Below we will present the proof of this result (originally proved here) because it is not specially hard and it contains an ingredient that we will encounter later in this post.
Proof: If is periodic, then it is not hard to convince oneself that
whenever
is a period of
.
Conversely, we note that we can assume that . Indeed, if
, then
is a constant word and the desired result is obvious. Next, we observe that
for all
(by definition). Therefore, the assumption that
implies that there exists
such that
.
By definition, the equality means that given any subword
of
of length
, there exists an unique way to select a letter
in order to extend
into a sub-word
of
of length
. In order words, the knowledge of any word of length
permits to reconstruct
. From this, it is not hard to see that
is periodic: indeed, since
, we see that there is a word
of length
appearing twice in
(it suffices to consider the
-first translates by
of any word of length
and observe that there must be a repetition somewhere because we dispose only of
distinct patterns for words of length
); since there is an unique way to extend
, we see that
consists of a repetition of the letters between two consecutives appearances of
, and, a fortiori,
is periodic.
As you just saw, an important aspect in the last part of the proof of Morse-Hedlund theorem is the recurrence of words (i.e., finite subwords appear infinitely often). In fact there is a whole literature dedicated to recurrent words, but we will not mention it here. Instead, let us just mention that, if is recurrent, then the following statements are equivalent:
is periodic
- the complexity function
is bounded
- there exists
such that
Also, a recurrent word such that
is called Sturmian word, and the so-called Thue-Morse sequence is a famous example of (uniformly) recurrent word that is not periodic (nor eventually periodic).
2. Nivat’s conjecture
Let us consider words indexed by ,
, i.e., elements of
where
is our preferred alphabet.
Note that, for , the notion of periodicity can be generalized in several ways. For her purposes, Bryna considered the following two notions:
Definition 2 We say that
is periodic if there exists
such that
. In other words,
is periodic if the restriction of
to some line (
-dimensional subspace) is periodic. Similarly, we say that
is fully periodic if it is periodic along a set of
linearly independent lines.
Analogously to the case of words in , we can introduce complexity functions
counting the number of configurations of a rectangle
, or, more generally, given
, we can define
as the number of configurations obtained after translating
around
.
The next proposition says that the characterization of full periodicity is very similar to the case of :
Proposition 3
is fully periodic if and only if the complexity function
is bounded.
Proof: It is clear that if is fully periodic then
is bounded.
Conversely, if is bounded, the idea is that we can reduce our task to the Morse-Hedlund theorem: indeed, if
, then, it is not hard to convince oneself that
is a period for
.
On the other hand, the characterization of periodicity is a more subtle task, and, in fact, Nivat’s conjecture concerns the following partial characterization of periodicity for words in :
Nivat’s conjecture (1997). Let . If there are
such that
, then
is periodic.
Note that Nivat’s conjecture is “optimal” in the following sense: by taking and by letting
be the aperiodic word given by
and
elsewhere, then
.
Also, Nivat’s conjecture is a “two-dimensional conjecture”: Tijdeman observed that, for and
, the aperiodic word
given by
,
and
otherwise (where
is fixed) satisfies
; furthemore, given
and
, Sander and Tijdeman constructed aperiodic words
in
such that
.
Finally, as it was noticed by J. Cassaigne, and Berthé and Vuillon, there is no converse to Nivat’s conjecture: there are periodic words in
such that
for all
.
Currently, we dispose of some results towards Nivat’s conjecture:
- Sander and Tijdeman (2002) showed that if
or
for some
, then
is periodic.
- Epifanio, Koskas and Mignosi (2003) proved that if
for some
, then
is periodic.
- Quas and Zamboni (2004) improved the result of the previous item by showing that if
for some
, then
is periodic.
The main result of Bryna’s talk was the following theorem joint with V. Cyr:
Theorem 4 (Cyr-Kra) If
for some
, then
is periodic.
As Bryna pointed out, the proof of this result is dynamical in nature, and, thus, we will need to introduce a couple of definitions.
Let us equip our finite alphabet with the discrete topology, and let us equip
with the product topology. We denote by
the shift dynamics of
on
:
for each . Note that, for our choice of topology,
is continuous.
Given , let us denote by
the closure of the orbit of
, i.e.,
As it is well-known, the orbit closure is intimately related to the combinatorial properties of
. For example, the reader is invited to check that
is periodic if and only if
doesn’t act faithfully on
, and, for
,
is fully (i.e., doubly) periodic if and only if
is finite.
Besides the shift dynamics, we will also need the notion of (non-)expansive subspaces for a action. In order to motivate this definition, let us firstly recall the notion of expansiveness in the sense of R. Bowen:
Definition 5 Let
be a compact metric space and
a homeomorphism of
. We say that
is expansive if there exists
such that if
for all
then
. In other words,
is expansive if we can “reasonably separate” (from a fixed amount
) any pair of distinct points by iterating them.
In 1997, Boyle and Lind generalized this notion for -actions:
Definition 6 (Boyle and Lind) Let
be a compact metric space and
a continuous
-action on
. We say that
is expansive if there are a expansiveness radius
and a expansiveness constant
such that if
for all
with
, then
. (Here,
is the Euclidean distance.) In other words,
is expansive if we can reasonaly separate any pair of distinct point by iterating them using elements of
approximatively pointing in the direction of
.
For our preferred example , we have that
is expansive if there exists
such that if
for all
, then
.
In what follows, we will be interested in non-expansive subspaces.
Before passing to abstract results, let us give the following concrete (and instructive) example. Consider and consider the subset
of
consisting of all
such that
In the literature, the shift dynamics on is known as Ledrappier’s 3-dots systems. This dynamical system has several interesting properties (see, e.g, this blog post of Terence Tao for the relationship between this example and Rokhlin’s mixing problem), but, for the sake of her talk, Bryna mentioned just that it has three non-expansive lines, namely:
After this example, it is time to state some abstract results:
Theorem 7 (Boyle and Lind) If
is an infinite compact metric space with a continuous
action, then, for each
, there exists a non-expansive subspace of
of dimension
.
By taking and
, one has the following corollary:
Corollary 8 For
,
is doubly (i.e., fully) periodic
![]()
is finite
every
-dimensional subspace of
is expansive.
In this context, V. Cyr and B. Kra actually show the following result:
Theorem 9 (Cyr and Kra) Let
be a word such that
. Assume that there exists an unique non-expansive subspace of dimension for the shift dynamics on
. Then,
is periodic (but not doubly periodic).
The basic idea behind this theorem is that all periods of belong to the unique non-expansive line.
Anyhow, from this theorem, one can deduce Nivat’s conjecture if we can show that there is at most one non-expansive subspace. In order to show this last property, Cyr and Kra need the hypothesis :
Theorem 10 (Cyr and Kra) Let
be a word such that
for some
. Then, there is at most one non-expansive direction.
In summary, for :
is doubly periodic if and only if there is no non-expansive
-dimensional subspaces.
- if there is an unique non-expansive
-dimensional subspace, then
is periodic but not doubly periodic.
- in order to rule out the possible existence of at least two non-expansive
-dimensional subspaces, one needs the assumption
.
At this point, Bryna used the few minutes left to say a few words about the proofs of these results. Firstly, she mentioned that, similarly to the strategy used in the proof of Morse-Hedlund theorem, the basic idea is: one notices that if , then
, and one looks for
so that this inequality “stabilizes”.
Secondly, she made the previous paragraph a little more precise by introducing the notion of discrepancy
and by recalling the following lemma (cf. the proof of Lemma 2.1 in Cyr-Kra paper):
Lemma 11 If
and
, then either
or every
-coloring of
uniquely extends to a
-coloring of
.
Also, she noticed that the hypothesis of Nivat’s conjecture gives a rectangle such that
, and, by definition,
.
Then, she said that these properties combine “in a way similar to the proof of Morse-Hedlund theorem” to give the proposition:
Proposition 12 There exists
such that, for all
, every
-coloring of
extends uniquely to a
-coloring of
.
Finally, Bryna mentioned that this set plays the role of the interval
in the proof of Morse-Hedlund theorem, but, in order to be able to use
in the same that we used
, Bryna told us that one needs to control the geometry of
. In particular, she told that Cyr and her shows that
is convex and, from the assumption
, it is possible to prove that
occupies more than half of the rectangle
, and she concluded the talk by saying that essentially the convexity and the largeness of
(inside
) are sufficient to conclude the their results.
Those of us who know Bryna are not surprised by such feats of simultaneity. What you didn’t notice was that, during the talk, she was also thinking about what wine she was going to drink in the evening while also tapping out the Kreutzer sonata with her foot.
By: galoisrepresentations on February 6, 2013
at 4:59 am