Last January 8, 2020, Jialun Li gave the talk “Decrease of Fourier coefficients of stationary measures on the circle” in the “flat seminar” that I co-organize with Anton Zorich once per month.
In this post, I’ll transcript my notes of this nice talk (while taking full responsibility for any errors/mistakes in what follows).
1. Introduction
1.1. Stationary measures
Consider the linear action of on
induces an action on the projective space
. For later use, recall that
via
Given a probability measure on
, we can build a Markov chain / random walk whose steps consist into taking points
into
where
is chosen accordingly with the law of
.
The absence of hypothesis on might lead to uninteresting random walks: in fact, if a point
is stabilized by two elements
, then the random walk starting at
associated to
is not very interesting.
For this reason, we shall assume that
Hypothesis (i): the support of generates a Zariski-dense semigroup
.
Remark 1 By Tits alternative, in our current setting of
, the hypothesis (i) can be reformulated by replacing “Zariski-dense” with “not solvable”.
As it was famously established by Furstenberg, the random walks associated to have a well-defined asymptotic behaviour whenever (i) is fulfilled:
Theorem 1 (Furstenberg) Under (i), there exists (an unique) probability measure
on
such that, for all
,
as
. Here, the convolution of
with a probability measure
on
is a probability measure
on
defined as
so that
is the distribution of points obtained from
after
steps of the Markov chain associated to
.
In the literature, is called Furstenberg measure, and it is an important example of
–stationary measure, i.e., a probability measure on
which is “invariant on average”:
1.2. Lyapunov exponents
The stationary measure can be used to describe the growth of the norms of random products
associated to
-almost every
whenever
satisfies (i) and its first moment is finite:
Theorem 2 (Furstenberg, Guivarch–Raugi) If
has finite first moment, i.e.,
and
satisfies (i), then
for
-almost every
.
The quantity is called Lyapunov exponent.
1.3. Regularity of stationary measures
The Furstenberg measure dictates the distribution of the Markov chains associated to and, for this reason, it is natural to inquiry about the regularity properties of stationary measures.
In this direction, Guivarch showed that the Furstenberg measures have a certain regularity when satisfies (i) and its exponential moment is finite:
Hypothesis (ii): there exists with
.
Theorem 3 (Guivarch) Under (i) and (ii), there are
and
such that
for all
and
(where
is the interval of radius
centered at
). In particular,
has no atoms.
More recently, Jialun Li established in this article here another regularity result by showing the decay of the Fourier coefficients
(where ). More concretely, he proved that:
Theorem 4 (Li) Under (i) and (ii), we have
. In other words,
is a Rajchman measure.
In a certain sense, the role of assumption (i) in the previous theorem is to avoid the following kind of example:
Example 1 Let
with
Note that the semigroup generated by
is not Zariski dense in
(as
and
are upper-triangular).We affirm that there is no decay of Fourier coefficients in this situation. Indeed, recall that if we identify
with
via
, then
acts on
via Möbius transformations, i.e., an element
acts on
as
In particular,
,
, and the Fourier coefficients of the stationary measure given by the standard Hausdorff measure on middle-third Cantor set do not decay to zero.In a similar vein, if
is a real number such that
is a Pisot number, then
with
admits a stationary measure
(called the Bernoulli convolution of parameter
describing the distribution of the points
where
with probability
) whose Fourier coefficients do not decay.
The proof of Theorem 4 is based on a renewal theorem. More concretely, given a function , let
By thinking of as a smooth version of the characteristic function of an interval
, we see that
is “counting random products
with norm in the interval
”. In this context, Guivarch and Le Page established the following renewal theorem:
Theorem 5 (Guivarch–Le Page) Under (i) and (ii), one has
as
.
Remark 2 Another important fact in the proof of Theorem 4 is the non-arithmeticity of the Jordan projections
of the elements of
, i.e., the fact that these Jordan projections generate a dense subgroup of
(whenever (i) is satisfied).
Since we will come back later to the discussion of deriving the decay of Fourier coefficients (e.g., Theorem 4) from a renewal theorem, let us now move forward in order to introduce the main result of this post, namely, a quantitative version of Theorem 4.
2. Quantitative decay of Fourier coefficients
The central result of this post is inspired by the following theorem of Bourgain and Dyatlov.
Theorem 6 (Bourgain–Dyatlov) If
is the Patterson–Sullivan measure associated to a Schottky subgroup of
, then there exists
(depending only on the dimension of
, i.e., the Hausdorff dimension of the limit set of the Schottky subgroup) such that
for all
.
The method of proof of this result is based on the so-called discretized sum-product estimates from additive combinatorics.
Interestingly enough, this result can be interpreted as a decay of Fourier coefficients of certain stationary measures thanks to the following theorem:
Theorem 7 (Furstenberg, Sullivan, …) The Patterson–Sullivan measure
of a Schottky subgroup coincides with the stationary measure
of some probability measure
on
satisfying (i) and (ii).
Remark 3 We saw the proof of a version of this result for cocompact lattices of
in Proposition 14 of this blog post here.
The previous theorems suggest that a decay of Fourier coefficients of the Furstenberg measure associated to a probability measure on
satisfying (i) and (ii). This statement was recently proved by Jialun Li in this article here.
Theorem 8 (Li) If
is a probability measure on
satisfying (i) and (ii), then there exists
such that the Furstenberg measure
associated to
verifies
for all
.
Remark 4 Actually, Li’s theorem is stated in his article for any real split semisimple Lie group
.
The proof of this result is also based on a discretized sum-product estimate. Moreover, this statement is closely related to spectral gap of transfer operators and a renewal theorem:
Theorem 9 (Li) Let
be a probability measure on
verifying (i) and (ii). Given
, consider the transfer operator
acting on
(with
small enough). Then,we have the following spectral gap property: there exists
such that the spectral radius of
satisfies
for all
.
Theorem 10 (Li) Under (i) and (ii), there exists
such that the renewal operator
satisfies
for all
.
In his article, Li establishes first Theorem 8 from a discretized sum-product estimate, and subsequently Theorems 9 and 10 are deduced from Theorem 8.
Nevertheless, Li pointed out in his talk that Theorems 8, 9 and 10 are “morally equivalent” to each other. In fact,
- Theorem 8
Theorem 9: the Fourier decay can be used to prove spectral gap for transfer operators via the so-called Dolgopyat method (which was discussed in this blog post here);
- Theorem 9
Theorem 10: the spectral gap for transfer operators allows to deduce the renewal theorem because some elementary calculations reveal that
is related to
;
- Theorem 10
Theorem 8: let us finally fulfil our promise made in the end of the previous section by briefly explaining the idea of the derivation of the Fourier decay in Theorem 8 from the renewal theorem in Theorem 10; since
, the
th Fourier coefficient of the Furstenberg measure is
by Cauchy–Schwarz inequality, the control of
is reduced to the study of
since
, we see that the size of the integral above depends on the “number of random products
with norm
in a given interval”, and the answer to this kind of “counting problem” is encoded in the asymptotic property of the renewal operator
provided by Theorem 10.
Remark 5 The analog of Theorem 10 in Abelian settings is false: the random walks driven by a finitely supported law
on
which is not arithmetic (i.e., its support generates a dense subgroup) verify a renewal theorem
for
, but the error term is never exponential because
grows polynomially with
. (Of course, this phenomenon is avoided in the context of
thanks to the fact that the Zariski-density assumption (i) on
ensures an exponential growth of
with
.)
Leave a Reply